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2.6=x^2-12.5
We move all terms to the left:
2.6-(x^2-12.5)=0
We get rid of parentheses
-x^2+12.5+2.6=0
We add all the numbers together, and all the variables
-1x^2+15.1=0
a = -1; b = 0; c = +15.1;
Δ = b2-4ac
Δ = 02-4·(-1)·15.1
Δ = 60.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{60.4}}{2*-1}=\frac{0-\sqrt{60.4}}{-2} =-\frac{\sqrt{}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{60.4}}{2*-1}=\frac{0+\sqrt{60.4}}{-2} =\frac{\sqrt{}}{-2} $
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